Sodium Hydroxide → N-isopropyl-N-(3,4-methylenedioxyphenyl)thiourea
Reaction equation
O1CCOCC1.[OH-].[Na+].[CH:9]([N:12]([C:24]1[CH:29]=[CH:28][C:27]2[O:30][CH2:31][O:32][C:26]=2[CH:25]=1)[C:13]([NH:15]C(=O)C1C=CC=CC=1)=[S:14])([CH3:11])[CH3:10]>O>[CH:9]([N:12]([C:24]1[CH:29]=[CH:28][C:27]2[O:30][CH2:31][O:32][C:26]=2[CH:25]=1)[C:13]([NH2:15])=[S:14])([CH3:11])[CH3:10]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 15 °C
Procedure
To a stirred solution consisting of 45 ml. of dioxane and 200 ml. of water is added 27 grams of sodium hydroxide and the whole stirred until complete solution takes place. To this solution is added 17 grams of N-isopropyl-N-(3,4-methylenedioxyphenyl)-N'-benzoyl thiourea. The resulting mixture is heated to reflux for 48 hours and then cooled to 15°C. The resulting white solid is crystallized from benzene to obtain N-isopropyl-N-(3,4-methylenedioxyphenyl)-thiourea melting at 149°-151°C.
Workup
- temperatureThe resulting mixture is heated
- temperatureto reflux for 48 hours
- customThe resulting white solid is crystallized from benzene
Sources & evidence
- ORD record
- ord-314d0f9e9c354830a9f0c12ac0e3f59e
- Source dataset
- uspto-grants-1976_12
- Patent number
- US03997564
Reaction notes
Loading…