HRID1979837

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID14798

Sodium Hydroxide

HNaO

HCID5284359

未命名化合物

结构：CCON=C(CC)C1=C(O)CC(c2ccc(NS(C)(=O)=O)cc2)CC1=O

HCID136102391

未命名化合物

PRODUCTS

生成物

结构：CCON=C(CC)C1=C([O-])CC(c2ccc(NS(C)(=O)=O)cc2)CC1=O.CCON=C(CC)C1=C([O-])CC(c2ccc(NS(C)(=O)=O)cc2)CC1=O.[Ca+2]

HCID86739763

未命名化合物

PROCEDURE

实验过程

Into 20 ml of an aqueous solution containing 2% of sodium hydroxide was dissolved 1.9 g of 2-[1-(ethoxyimino)propyl]-5-(4-methanesulfonamidophenyl)-3-hydroxy-2-cyclohexen-1-one and to the solution was added 3 cc of an aqueous solution containing 10% of calcium chloride at room temperature. The water was removed under reduced pressure and the residue was dissolved in ethanol and an insoluble sodium chloride was separated with a filtering step. The ethanol was distilled off under reduced pressure and 1.5 g of white powder having a melting point of 250° C. or more was obtained.

WORKUP

后处理

customThe water was removed under reduced pressure
dissolutionthe residue was dissolved in ethanol
customan insoluble sodium chloride was separated with a filtering step
distillationThe ethanol was distilled off under reduced pressure and 1.5 g of white powder
customwas obtained

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-8ed58d8cfe3f4fa0a43fe80625df0a13
来源数据集: uspto-grants-1984_11
DOI: 10.6084/m9.figshare.5104873.v1
专利: US04482740
来源说明: uspto-grants-1984_11

反应 SMILES

[OH-].[Na+].[CH2:3]([O:5][N:6]=[C:7]([C:10]1[C:11](=[O:28])[CH2:12][CH:13]([C:17]2[CH:22]=[CH:21][C:20]([NH:23][S:24]([CH3:27])(=[O:26])=[O:25])=[CH:19][CH:18]=2)[CH2:14][C:15]=1[OH:16])[CH2:8][CH3:9])[CH3:4].[Cl-].[Ca+2:30].[Cl-]>>[CH2:3]([O:5][N:6]=[C:7]([C:10]1[C:11](=[O:28])[CH2:12][CH:13]([C:17]2[CH:22]=[CH:21][C:20]([NH:23][S:24]([CH3:27])(=[O:26])=[O:25])=[CH:19][CH:18]=2)[CH2:14][C:15]=1[O-:16])[CH2:8][CH3:9])[CH3:4].[Ca+2:30].[CH2:3]([O:5][N:6]=[C:7]([C:10]1[C:11](=[O:28])[CH2:12][CH:13]([C:17]2[CH:22]=[CH:21][C:20]([NH:23][S:24]([CH3:27])(=[O:26])=[O:25])=[CH:19][CH:18]=2)[CH2:14][C:15]=1[O-:16])[CH2:8][CH3:9])[CH3:4]