Water → Z-Phe(4-F)-N-Me-Val-N-Me-Tyr(3-tBu)-NH2
Reaction equation
[NH:1]([C:14]([O:16][CH2:17][C:18]1[CH:23]=[CH:22][CH:21]=[CH:20][CH:19]=1)=[O:15])[C@H:2]([C:11]([OH:13])=O)[CH2:3][C:4]1[CH:9]=[CH:8][C:7]([F:10])=[CH:6][CH:5]=1.[NH:24]([CH3:49])[C@H:25]([C:29]([N:31]([CH3:48])[C@H:32]([C:45]([NH2:47])=[O:46])[CH2:33][C:34]1[CH:39]=[CH:38][C:37]([OH:40])=[C:36]([C:41]([CH3:44])([CH3:43])[CH3:42])[CH:35]=1)=[O:30])[CH:26]([CH3:28])[CH3:27].O>C1COCC1>[NH:1]([C:14]([O:16][CH2:17][C:18]1[CH:23]=[CH:22][CH:21]=[CH:20][CH:19]=1)=[O:15])[C@H:2]([C:11]([N:24]([CH3:49])[C@H:25]([C:29]([N:31]([CH3:48])[C@H:32]([C:45]([NH2:47])=[O:46])[CH2:33][C:34]1[CH:39]=[CH:38][C:37]([OH:40])=[C:36]([C:41]([CH3:44])([CH3:42])[CH3:43])[CH:35]=1)=[O:30])[CH:26]([CH3:28])[CH3:27])=[O:13])[CH2:3][C:4]1[CH:5]=[CH:6][C:7]([F:10])=[CH:8][CH:9]=1Participants
5
Procedure
To a solution of Z-Phe(4-F)—OH (1.09 g, 3.44 mmol), N-Me-Val-N-Me-Tyr(3-tBu)-NH2 (1.04 g, 2.87 mmol) and CMPI (878 mg, 3.44 mmol) in THF (30 ml), TEA (0.96 ml, 6.88 mmol) was added under cooling with ice and stirred at room temperature overnight. The reaction mixture was mixed with water and extracted with ethyl acetate. The organic layer was washed with saturated brine, dried over anhydrous magnesium sulfate and evaporated to remove the solvent under reduced pressure; the thus obtained residue was subjected to silica gel column chromatography (developing solvent: n-hexane:ethyl acetate=1:3) to give Z-Phe(4-F)-N-Me-Val-N-Me-Tyr(3-tBu)-NH2 (1.73 g, 91%).
Workup
- temperatureunder cooling with ice
- extractionextracted with ethyl acetate
- washThe organic layer was washed with saturated brine
- dry with materialdried over anhydrous magnesium sulfate
- customevaporated
- customto remove the solvent under reduced pressure
Sources & evidence
- ORD record
- ord-c4f25e93c12f4065a50008f78c7ac915
- Source dataset
- uspto-grants-2009_06
- Patent number
- US07553969B1
Reaction notes
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