Boc-Phe(2-F)-N-Me-Val-N-Me-Tyr(3-tBu)-NH2 → Phe(2-F)-N-Me-Val-N-Me-Tyr(3-tBu)-NH2
Reaction equation
[NH:1](C(OC(C)(C)C)=O)[C@H:2]([C:11]([N:13]([CH3:38])[C@H:14]([C:18]([N:20]([CH3:37])[C@H:21]([C:34]([NH2:36])=[O:35])[CH2:22][C:23]1[CH:28]=[CH:27][C:26]([OH:29])=[C:25]([C:30]([CH3:33])([CH3:32])[CH3:31])[CH:24]=1)=[O:19])[CH:15]([CH3:17])[CH3:16])=[O:12])[CH2:3][C:4]1[C:5]([F:10])=[CH:6][CH:7]=[CH:8][CH:9]=1>C(Cl)Cl.C(O)(C(F)(F)F)=O>[NH2:1][C@H:2]([C:11]([N:13]([CH3:38])[C@H:14]([C:18]([N:20]([CH3:37])[C@H:21]([C:34]([NH2:36])=[O:35])[CH2:22][C:23]1[CH:28]=[CH:27][C:26]([OH:29])=[C:25]([C:30]([CH3:31])([CH3:32])[CH3:33])[CH:24]=1)=[O:19])[CH:15]([CH3:16])[CH3:17])=[O:12])[CH2:3][C:4]1[C:5]([F:10])=[CH:6][CH:7]=[CH:8][CH:9]=1Participants
4
Reactant 1
Product 1
Reagents, catalysts & solvents 2
Procedure
To a solution of Boc-Phe(2-F)-N-Me-Val-N-Me-Tyr(3-tBu)-NH2 (0.33 g, 0.525 mmol) in methylene chloride (3 ml), TFA (1.5 ml) was added, stirred for 15 min. and then evaporated to remove the solvent under reduced pressure. The residue was mixed with methylene chloride, washed with a saturated aqueous NaHCO3 solution, dried over anhydrous magnesium sulfate and evaporated to remove the solvent under reduced pressure. The thus obtained residue was subjected to silica gel column chromatography (developing solvent: chloroform:methanol:aqueous ammonia=40:1:0.1) to give Phe(2-F)-N-Me-Val-N-Me-Tyr(3-tBu)-NH2 (235 mg, 85%).
Workup
- customevaporated
- customto remove the solvent under reduced pressure
- additionThe residue was mixed with methylene chloride
- washwashed with a saturated aqueous NaHCO3 solution
- dry with materialdried over anhydrous magnesium sulfate
- customevaporated
- customto remove the solvent under reduced pressure
Sources & evidence
- ORD record
- ord-01509db9dce14bbea592d6646822b480
- Source dataset
- uspto-grants-2009_06
- Patent number
- US07553969B1
Reaction notes
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