Phosphorus oxychloride → 2-Chloro-4-phenylthiazole
Reaction equation
[C:1]1([C:7]2[NH:8][C:9](=O)[S:10][CH:11]=2)[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.O=P(Cl)(Cl)[Cl:15]>>[Cl:15][C:9]1[S:10][CH:11]=[C:7]([C:1]2[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=2)[N:8]=1Participants
3
Procedure
4-Phenyl-3H-thiazol-2-one (5 g, 28.2 mmol) was dissolved in POCl3 (30 mL), and the mixture was refluxed overnight. The mixture was concentrated in vacuum, and the residue was purified by column chromatography to give 2-chloro-4-phenylthiazole (3.1 g, 57%).
Workup
- temperaturethe mixture was refluxed overnight
- concentrationThe mixture was concentrated in vacuum
- customthe residue was purified by column chromatography
Sources & evidence
- ORD record
- ord-1cc5365b28cf420f811c50c15b2f1e98
- Source dataset
- uspto-grants-2013_11
- Patent number
- US08575156B2
Reaction notes
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