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HRID2038391

反应详情

EQUATION

反应方程式

HRID 2038391 的结构方程式

REACTANTS

反应物

2
结构：N#Cc1cc(-c2sc(C(=O)O)nc2-c2ccc(F)c(Cl)c2)ccc1F
HCID67568353

未命名化合物

结构：N#Cc1cc(-c2sc(C(=O)N3CNC(=O)C3)nc2-c2cccc(Cl)c2)ccc1F
HCID70315200

未命名化合物

PRODUCTS

生成物

1
结构：N#Cc1cc(-c2sc(C(=O)N3CNC(=O)C3)nc2-c2ccc(F)c(Cl)c2)ccc1F
HCID50942988

未命名化合物

PROCEDURE

实验过程

The preparation of the title compound takes place in analogy to the synthesis of the compound from Example 5 starting with the compound from Example 15A. 17.3 mg (35% of theory) of the title compound are obtained.