Nitric Acid → Dibismuth molybdenum hexaoxide

HRID 2057795Notes

Reaction equation

HRID 2057795 reaction equation
[N+]([O-])(O)=[O:2].N.N.N.N.N.N.[OH2:11].O.O.O.O[Mo:16](O)(=O)=O.O[Mo](O)(=O)=O.O[Mo](O)(=O)=O.O=[Mo](=O)=O.O=[Mo](=O)=O.O=[Mo](=O)=O.O=[Mo](=O)=O.[N+]([O-])([O-])=O.[Bi+3:50].[N+]([O-])([O-])=O.[N+]([O-])([O-])=O.N.N.N.N.N.N.O.O.O.O.O.O.O.O.O.O.O.O.O.O.O.O.O.O.O.O.O.O.O.O.[Mo:89].[Mo].[Mo].[Mo].[Mo].[Mo].[Mo].[NH4+].[OH-]>O>[O-2:2].[O-2:11].[O-2:2].[O-2:2].[O-2:2].[O-2:2].[O-2:2].[O-2:2].[O-2:2].[Mo:16].[Mo:89].[Bi+3:50].[Bi+3:50]

Participants

7

Reactant 5

HCID 944Nitric AcidHCID 14923Ammonium HydroxideHCID 25488Azane;molybdenum;tetracosahydrateHCID 107711Bismuth nitrateHCID 16211167Ammonium paramolybdate tetrahydrate

Product 1

HCID 159680Dibismuth molybdenum hexaoxide

Reagents, catalysts & solvents 1

HCID 962WaterSolvent

Procedure

10.91 g Bi(NO3)3.5H2O was dissolved in about 40 ml. of a 10% aqueous HNO3 solution. 5.96 g of (NH4)6Mo7O24.4H2O was dissolved in about 75 ml. of H2O with heating. The bismuth nitrate solution was added with constant stirring to the ammonium heptamolybdate solution. The pH of the mixture was then adjusted to 2.5 to 3 by the dropwise addition of reagent grade NH4OH. The mixture was then stirred for 1 hour to produce a bismuth molybdate slurry.

Sources & evidence

ORD record
ord-20bf7d0a4b50411e963506129c9e00ec
Source dataset
uspto-grants-1980_07
Patent number
US04212766

Reaction notes

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