Hydrochloric Acid → Zirconium phosphate
Reaction equation
O(Cl)Cl.[Zr:4].Cl.[P:6](=[O:10])([OH:9])([OH:8])[OH:7]>O>[P:6]([O-:10])([O-:9])([O-:8])=[O:7].[Zr+4:4].[P:6]([O-:10])([O-:9])([O-:8])=[O:7].[P:6]([O-:10])([O-:9])([O-:8])=[O:7].[P:6]([O-:10])([O-:9])([O-:8])=[O:7].[Zr+4:4].[Zr+4:4]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
Three hundred and twenty-two (322) g of zirconium oxychloride (ZrOCl2.8H2O) is dissolved in 4 liter of water, and to this solution is added 200 g of concentrated hydrochloric acid. To the resulting acidic solution is added further aqueous solution consisting of 250 g of 98% phosphoric acid and 5 liter of water, and, after stirred for about 20 minutes, the solution is left overnight. Precipitates of zirconium phosphate formed in the solution are centrifuged, washed with water sufficiently and dried at about 80° C. The solid matter obtained is put again in a water to be broken, and the resulting precipitates in the water are centrifuged, dried and sieved to prepare the desired compound particles of 24-32 meshes.
Workup
- additionTo the resulting acidic solution is added further aqueous solution
- waitthe solution is left overnight
- customPrecipitates of zirconium phosphate
- customformed in the solution
- washwashed with water sufficiently
- customdried at about 80° C
- customThe solid matter obtained
- customthe resulting precipitates in the water
- customdried
- filtrationsieved
- customto prepare the desired compound particles of 24-32 meshes
Sources & evidence
- ORD record
- ord-943f330a95604320ac5d043104e63b93
- Source dataset
- uspto-grants-1982_03
- Patent number
- US04318417
Reaction notes
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