2-Methoxyethylamine → HCID 11639365, compound

HRID 2069220Notes

Reaction equation

HRID 2069220 reaction equation
F[C:2]1[CH:3]=[C:4]2[C:9](=[CH:10][C:11]=1[N+:12]([O-:14])=[O:13])[NH:8][C:7](=[O:15])[N:6]([NH:16][S:17]([CH3:20])(=[O:19])=[O:18])[C:5]2=[O:21].[CH3:22][O:23][CH2:24][CH2:25][NH2:26]>>[CH3:22][O:23][CH2:24][CH2:25][NH:26][C:2]1[CH:3]=[C:4]2[C:9](=[CH:10][C:11]=1[N+:12]([O-:14])=[O:13])[NH:8][C:7](=[O:15])[N:6]([NH:16][S:17]([CH3:20])(=[O:19])=[O:18])[C:5]2=[O:21]

Participants

3

Reactant 2

HCID 80182-MethoxyethylamineHCID 58964482N-(6-fluoro-7-nitro-2,4-dioxo-1,4-dihydro-2H-quinazolin-3-yl)-methanesulfonamide

Product 1

HCID 11639365HCID 11639365, compoundYield 36%

Procedure

N-(6-Fluoro-7-nitro-2,4-dioxo-1,4-dihydro-2H-quinazolin-3-yl)-methanesulfonamide (20 mg, 0.0628 mmol) is reacted with 2-methoxy-ethylamine according to the GPA affording 8.5 mg (36%) of a red powder. Rt=3.84 min.

Sources & evidence

ORD record
ord-095ef1e5f462443d9e179115acf19720
Source dataset
uspto-grants-2012_10
Patent number
US08299085B2

Reaction notes

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