Water → Fmoc-Phe-N-Me-Val-Tyr-NH2

HRID 2085560Notes

Reaction equation

HRID 2085560 reaction equation
[NH:1]([CH3:22])[C@H:2]([C:6]([N:8](C)[C@H:9]([C:18]([NH2:20])=[O:19])[CH2:10][C:11]1[CH:16]=[CH:15][C:14]([OH:17])=[CH:13][CH:12]=1)=[O:7])[CH:3]([CH3:5])[CH3:4].[NH:23]([C:35]([O:37][CH2:38][CH:39]1[C:51]2[C:46](=[CH:47][CH:48]=[CH:49][CH:50]=2)[C:45]2[C:40]1=[CH:41][CH:42]=[CH:43][CH:44]=2)=[O:36])[C@H:24]([C:32](O)=[O:33])[CH2:25][C:26]1[CH:31]=[CH:30][CH:29]=[CH:28][CH:27]=1.O>C1COCC1>[NH:23]([C:35]([O:37][CH2:38][CH:39]1[C:51]2[C:46](=[CH:47][CH:48]=[CH:49][CH:50]=2)[C:45]2[C:40]1=[CH:41][CH:42]=[CH:43][CH:44]=2)=[O:36])[C@H:24]([C:32]([N:1]([CH3:22])[C@H:2]([C:6]([NH:8][C@H:9]([C:18]([NH2:20])=[O:19])[CH2:10][C:11]1[CH:12]=[CH:13][C:14]([OH:17])=[CH:15][CH:16]=1)=[O:7])[CH:3]([CH3:4])[CH3:5])=[O:33])[CH2:25][C:26]1[CH:31]=[CH:30][CH:29]=[CH:28][CH:27]=1

Participants

5

Procedure

To a solution of N-Me-Val-N-Me-Tyr-NH2(185 mg, 0.603 mmol) in THF (6 ml), Fmoc-Phe-OH (304 mg, 0.784 mmol), CMPI (200 mg, 0.784 mmol) and TEA (0.168 ml, 1.21 mmol) were added under cooling with ice, followed by stirring at room temperature overnight. The reaction mixture was mixed with water and extracted with ethyl acetate. The organic layer was washed with saturated brine, dried over magnesium sulfate and evaporated to remove the solvent under reduced pressure; the thus obtained residue was subjected to silica gel column chromatography (developing solvent: ethyl acetate:n-hexane=2:1) to give the titled compound (197 mg, 48%).

Workup

  1. temperatureunder cooling with ice
  2. extractionextracted with ethyl acetate
  3. washThe organic layer was washed with saturated brine
  4. dry with materialdried over magnesium sulfate
  5. customevaporated
  6. customto remove the solvent under reduced pressure

Sources & evidence

ORD record
ord-cc55d8a151dc4a29b991afbecd76ce09
Source dataset
uspto-grants-2004_04
Patent number
US06720433B2

Reaction notes

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