HRID21153

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID8471

Triethylamine

C6H15N

HCID2734272

5-chloro-2-methoxybenzenesulfonyl chloride

C7H6Cl2O3S

结构：CC(C)(C)OC(=O)n1c(-c2ccc(O)c3c2C(=O)NC3)cc2cc(CN3CCCCC3)ccc21

HCID68493222

未命名化合物

PRODUCTS

生成物

结构：COc1ccc(Cl)cc1S(=O)(=O)Oc1ccc(-c2cc3cc(CN4CCCCC4)ccc3n2C(=O)OC(C)(C)C)c2c1CNC2=O

HCID86628258

未命名化合物

收率 42.7%

AUXILIARIES

试剂、催化剂与溶剂

溶剂HCID6342

Acetonitrile

C2H3N

PROCEDURE

实验过程

In a similar manner to Step 1 of Example 233, 4-hydroxy-7-[1-(tert-butoxycarbonyl)-5-(piperidinomethyl)indol-2-yl]isoindolinone (0.0279 g, 0.0604 mmol) was dissolved in acetonitrile (0.650 mL), and the solution was treated with triethylamine (0.0540 mL, 0.390 mmol) and 5-chloro-2-methoxybenzenesulfonyl chloride (0.0470 g, 0.195 mmol) to obtain 4-(2-methoxy-5-chlorobenzenesulfonyloxy)-7-[1-(tert-butoxycarbonyl)-5-(piperidinomethyl)indol-2-yl]isoindolinone (0.0172 g, yield 434).

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-6b4029bc985f42aabee55b997e1be15e
来源数据集: uspto-grants-2010_06
DOI: 10.6084/m9.figshare.5104873.v1
专利: US07745641B2
来源说明: uspto-grants-2010_06

反应 SMILES

[OH:1][C:2]1[CH:10]=[CH:9][C:8]([C:11]2[N:12]([C:27]([O:29][C:30]([CH3:33])([CH3:32])[CH3:31])=[O:28])[C:13]3[C:18]([CH:19]=2)=[CH:17][C:16]([CH2:20][N:21]2[CH2:26][CH2:25][CH2:24][CH2:23][CH2:22]2)=[CH:15][CH:14]=3)=[C:7]2[C:3]=1[CH2:4][NH:5][C:6]2=[O:34].C(N(CC)CC)C.[Cl:42][C:43]1[CH:44]=[CH:45][C:46]([O:53][CH3:54])=[C:47]([S:49](Cl)(=[O:51])=[O:50])[CH:48]=1>C(#N)C>[CH3:54][O:53][C:46]1[CH:45]=[CH:44][C:43]([Cl:42])=[CH:48][C:47]=1[S:49]([O:1][C:2]1[CH:10]=[CH:9][C:8]([C:11]2[N:12]([C:27]([O:29][C:30]([CH3:31])([CH3:33])[CH3:32])=[O:28])[C:13]3[C:18]([CH:19]=2)=[CH:17][C:16]([CH2:20][N:21]2[CH2:26][CH2:25][CH2:24][CH2:23][CH2:22]2)=[CH:15][CH:14]=3)=[C:7]2[C:3]=1[CH2:4][NH:5][C:6]2=[O:34])(=[O:51])=[O:50]