Sodium Methoxide → HCID 69314682, compound
Reaction equation
CN(C)[CH:3]=[CH:4][C:5]([C:7]1[N:11]([CH:12]([CH3:14])[CH3:13])[C:10]([CH2:15][O:16][CH3:17])=[N:9][CH:8]=1)=O.C(=O)(O)O.[C:23]1([NH:29][C:30]([NH2:32])=[NH:31])[CH:28]=[CH:27][CH:26]=[CH:25][CH:24]=1.C[O-].[Na+]>CC(N(C)C)=O>[NH:29]([C:30]1[N:32]=[C:5]([C:7]2[N:11]([CH:12]([CH3:14])[CH3:13])[C:10]([CH2:15][O:16][CH3:17])=[N:9][CH:8]=2)[CH:4]=[CH:3][N:31]=1)[C:23]1[CH:28]=[CH:27][CH:26]=[CH:25][CH:24]=1Participants
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 110 °C
Procedure
5-(3-Dimethylaminoprop-2-en-1-oyl)-1-isopropyl-2-methoxymethylimidazole (Method 50; 1.26 g, 5 mmol), phenylguanidine hydrogen carbonate (1.09 g, 5.5 mmol) and sodium methoxide (594 mg, 11 mmol) were suspended in anhydrous DMA (10 ml) and the mixture heated at 110° C. for 3 hours. The volatiles were evaporated in vacuo the residues was suspended in water (50 ml). The solution was extracted DCM (3×50 ml). The combined extracts were washed with water (50 ml) and then brine (50 ml), dried and the volatiles removed by evaporation. The residue was purified by flash silica chromatography eluting with DCM:MeOH (100:0 increasing in polarity to 97:3) to give the title compound as brown oil. NMR: 1.43 (d, 6H), 3.30 (s, 3H), 4.56 (s, 2H), 5.54 (m, 1H), 6.96 (t, 1H), 7.05 (d, 1H), 7.24 (t,2H), 7.44 (s, 1H), 7.65 (d, 2H), 8.41 (d, 1H), 9.42 (s, 1H); m/z 324.
Workup
- customThe volatiles were evaporated in vacuo the residues
- extractionThe solution was extracted DCM (3×50 ml)
- washThe combined extracts were washed with water (50 ml)
- dry with materialbrine (50 ml), dried
- customthe volatiles removed by evaporation
- customThe residue was purified by flash silica chromatography
- washeluting with DCM:MeOH (100:0 increasing in polarity to 97:3)
Sources & evidence
- ORD record
- ord-c326c4f707b84ec5b304512f74f99986
- Source dataset
- uspto-grants-2008_10
- Patent number
- US07442697B2
Reaction notes
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