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HRID2118815

反应详情

EQUATION

反应方程式

HRID 2118815 的结构方程式

REACTANTS

反应物

3
结构：O=C([O-])[O-].[Ca+2]
HCID10112

Calcium carbonate

CCaO3

结构：CC1CCNCC1
HCID69381

Piperidine, 4-methyl-

C6H13N

结构：O=C(c1ccccc1)c1cc([N+](=O)[O-])ccc1Cl
HCID118591

2-Chloro-5-nitrobenzophenone

C13H8ClNO3

PRODUCTS

生成物

1
结构：CC1CCN(c2ccc([N+](=O)[O-])cc2C(=O)c2ccccc2)CC1
HCID15072430

未命名化合物

收率 88.4%

AUXILIARIES

试剂、催化剂与溶剂

1
结构：CCO
溶剂HCID702

Ethanol

C2H6O

PROCEDURE

实验过程

Proceeding as indicated in example 2, with 0.03 mole (7.8 g) of 2-chloro-5-nitro-benzophenone, 0.05 mole (5.7 cm3) of 4-methylpiperidine and 0.03 mole (4.1 g) of calcium carbonate in 80 cm3 of ethanol, 8.6 g (Yield: 88%) of the expected product are obtained. M.P. 81° C.