Lithium Hydroxide → HCID 69893790, compound
Reaction equation
C[O:2][C:3](=[O:54])[C@H:4]([CH2:6][C:7]([C:10](=[O:53])[C:11]1[CH:16]=[CH:15][CH:14]=[C:13]([NH:17][CH2:18][C:19]2[N:20]=[CH:21][N:22]([C:24]([C:37]3[CH:42]=[CH:41][CH:40]=[CH:39][CH:38]=3)([C:31]3[CH:36]=[CH:35][CH:34]=[CH:33][CH:32]=3)[C:25]3[CH:30]=[CH:29][CH:28]=[CH:27][CH:26]=3)[CH:23]=2)[C:12]=1[C:43]1[C:52]2[C:47](=[CH:48][CH:49]=[CH:50][CH:51]=2)[CH:46]=[CH:45][CH:44]=1)([CH3:9])[CH3:8])[NH2:5].[Li+].[OH-]>C1COCC1.O>[C:24]([N:22]1[CH:23]=[C:19]([CH2:18][NH:17][C:13]2[C:12]([C:43]3[C:52]4[C:47](=[CH:48][CH:49]=[CH:50][CH:51]=4)[CH:46]=[CH:45][CH:44]=3)=[C:11]([CH:16]=[CH:15][CH:14]=2)[C:10]([C:7]([CH3:9])([CH3:8])[CH2:6][C@@H:4]([C:3]([OH:54])=[O:2])[NH2:5])=[O:53])[N:20]=[CH:21]1)([C:25]1[CH:30]=[CH:29][CH:28]=[CH:27][CH:26]=1)([C:31]1[CH:32]=[CH:33][CH:34]=[CH:35][CH:36]=1)[C:37]1[CH:38]=[CH:39][CH:40]=[CH:41][CH:42]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
The compound of Example 388A (0.24 g, 0.34 mmoles) was dissolved in 10 mL of THF/H2O (2:1) and LiOH (0.029 g, 0.68 mmoles) was added. The reaction was stirred at room temperature for 2 h. The THF was evaporated and the residue dissolved in 15 mL water, and 1N HCl added to lower the pH to 2. The compound is then extracted with ethyl acetate (3×25 mL), dried and the solvents evaporated to afford the free carboxylic acid as a white solid. (0.20 g, 84%).
Workup
- customThe THF was evaporated
- dissolutionthe residue dissolved in 15 mL water
- addition1N HCl added
- extractionThe compound is then extracted with ethyl acetate (3×25 mL)
- customdried
- customthe solvents evaporated
Sources & evidence
- ORD record
- ord-58ba8f725afb4f55a918bf1c67e166db
- Source dataset
- uspto-grants-2004_02
- Patent number
- US06693123B2
Reaction notes
Loading…