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HRID21499

反应详情

EQUATION

反应方程式

HRID 21499 的结构方程式

REACTANTS

反应物

2
结构：Cl
HCID313

Hydrochloric Acid

ClH

结构：CCOC(=O)CNC(=O)N[C@@H](C(=O)OC)c1ccc(CNC(=O)OCc2ccccc2)cc1
HCID67799367

未命名化合物

PRODUCTS

生成物

1
结构：Cl.NCc1ccc([C@H]2NC(=O)N(CC(=O)O)C2=O)cc1
HCID67798814

未命名化合物

PROCEDURE

实验过程

280 mg of N-(1-(R)-(4-benzyloxycarbonylaminomethylphenyl-1-methoxycarbonylmethyl),N'-ethoxycarbonylmethylurea are boiled under reflux for 45 min in 4 ml of 6N HCl and the mixture is then concentrated and dried over KOH.

WORKUP

后处理

  1. concentrationthe mixture is then concentrated
  2. dry with materialdried over KOH