HRID2175102

反应详情

EQUATION

反应方程式

HRID 2175102 的结构方程式

PROCEDURE

实验过程

The preparation is carried out analogously to FS1008 starting from 21 mg (0.199 mmol) of (R)-4-aminobutane-1,2-diol and 80 mg (0.199 mmol) of 6-(5,5,8,8-tetramethyl-5,6,7,8-tetrahydronaphthalen-2-yl)-2,3,5,6-tetrahydro-1,2′-bipyridinyl-4-one. The product is in the form of the hydrochloride.