1-Bromo-4-fluorobenzene → 1-(4-Fluorophenyl)-2-(3-methoxyphenyl)ethanone

HRID 2178068Notes

Reaction equation

HRID 2178068 reaction equation
C1(C2C=CC=CC=2)C=CC(C(=O)CC2C=CC=CC=2)=CC=1.CON(C)[C:25](=[O:35])[CH2:26][C:27]1[CH:32]=[CH:31][CH:30]=[C:29]([O:33][CH3:34])[CH:28]=1.Br[C:38]1[CH:43]=[CH:42][C:41]([F:44])=[CH:40][CH:39]=1>>[F:44][C:41]1[CH:42]=[CH:43][C:38]([C:25](=[O:35])[CH2:26][C:27]2[CH:32]=[CH:31][CH:30]=[C:29]([O:33][CH3:34])[CH:28]=2)=[CH:39][CH:40]=1

Participants

4

Reactant 3

HCID 99931-Bromo-4-fluorobenzeneHCID 748171-(1,1'-Biphenyl)-4-yl-2-phenylethan-1-oneHCID 14918162N-Methoxy-2-(3-methoxyphenyl)-N-methylacetamide

Product 1

HCID 431599671-(4-Fluorophenyl)-2-(3-methoxyphenyl)ethanoneYield 37%

Procedure

Followed the procedure described in Synthesis of Intermediate 14 using N-methoxy-2-(3-methoxyphenyl)-N-methylacetamide and 1-bromo-4-fluorobenzene to give desired Intermediate 53 (260 mg, 37% yield).

Sources & evidence

ORD record
ord-5b3539c8bbdf400b9e979e2e018e6488
Source dataset
uspto-grants-2015_06
Patent number
US09067893B2

Reaction notes

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