HRID2180153

反应详情

EQUATION

反应方程式

HRID 2180153 的结构方程式

PROCEDURE

实验过程

Using an analogous procedure to that described in Example 20, 4-(4-fluoro-2-methylindol-5-yloxy)-7-hydroxy-6-methoxycinnoline (0.2 g, 0.5 mol), (prepared as described in Example 4), was reacted with 3-(hydroxymethyl)pyridine (60 μl, 0.9 mmol) to give 4-(4-fluoro-2-methylindol-5-yloxy)-6-methoxy-7-(3-pyridylmethoxy)cinnoline (80 mg, 32%).