9,9-Dichloro-9-silafluorene → 4-(3',5'-Bis-[t-butyl]phenyl)2-isopropylindene

HRID 2182003Notes

Reaction equation

HRID 2182003 reaction equation
Cl[Si]1(Cl)C2C=CC=CC=2C2C1=CC=CC=2.[C:16]([C:20]1[CH:21]=[C:22]([C:30]2[CH:38]=[CH:37][CH:36]=[C:35]3[C:31]=2[CH:32]=[C:33]([CH:39]([CH3:41])[CH3:40])[CH2:34]3)[CH:23]=[C:24]([C:26]([CH3:29])([CH3:28])[CH3:27])[CH:25]=1)([CH3:19])([CH3:18])[CH3:17].[Li]>C1COCC1>[C:16]([C:20]1[CH:21]=[C:22]([C:30]2[CH:38]=[CH:37][CH:36]=[C:35]3[C:31]=2[CH:32]=[C:33]([CH:39]([CH3:41])[CH3:40])[CH2:34]3)[CH:23]=[C:24]([C:26]([CH3:29])([CH3:28])[CH3:27])[CH:25]=1)([CH3:17])([CH3:18])[CH3:19]

Participants

4

Procedure

9,9-Dichloro-9-silafluorene (1.1 g, 8.5 mmol) was dissolved in 80 mL of THF. To this solution was slowly added lithium 4-(3′,5′-di-t-butylphenyl)-2-isopropylindene (3.0 g, 8.5 mmol) as a dry powder and the solution was stirred overnight. After this time, the solvent was removed in vacuo and the residue was taken up in diethyl ether. The solution as filtered through frit to remove LiCl and the solvent was removed in vacuo and used as a crude product (3.9 g) for the next step.

Workup

  1. customAfter this time, the solvent was removed in vacuo
  2. filtrationThe solution as filtered through frit
  3. customto remove LiCl
  4. customthe solvent was removed in vacuo

Sources & evidence

ORD record
ord-75bca41d992b4b36aeeb7bab6e0cf63f
Source dataset
uspto-grants-2005_05
Patent number
US06894179B2

Reaction notes

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