HRID2191037

反应详情

EQUATION

反应方程式

HRID 2191037 的结构方程式

PROCEDURE

实验过程

Compound 25.2 (19.3 mg, 0.431 mmol) was treated with concentrated NH4OH (2.2 mL, 0.02 M) and stirred at room temperature for 16 h. The solvent was removed in vacuo and the residue was treated with 1% AcOH (2 mL). Reverse phase HPLC afforded compound 25.3 (7.0 mg, 47% yield) as a white solid: 1H NMR (D2O, 300 MHz) 8.10 (s, 2H), 6.26 (m, 1H), 6.19 (m, 1H), 5.85 (m, 1H), 4.77 (m, 1H), 4.51 (m, 1H), 4.31 (m, 1H); 31P NMR (D2O, 121.4 MHz) 9.6; MS (ESI) m/z 344 [M+H]+.

WORKUP

后处理

  1. customThe solvent was removed in vacuo
  2. additionthe residue was treated with 1% AcOH (2 mL)