HRID2196509

反应详情

EQUATION

反应方程式

HRID 2196509 的结构方程式

PROCEDURE

实验过程

Following the same procedure as described for compound 12 (step 2, scheme 2, example 1c) except using 19 (935 mg, 2.73 mmol) instead of 11 to provide compound 20 (692 mg, 75%) as a yellow solid. LRMS (ESI): calc. 339.1; found 340.2 (MH)+.