HRID2196510

反应详情

EQUATION

反应方程式

HRID 2196510 的结构方程式

PROCEDURE

实验过程

Following the same procedure as described for compound 13 (step 3, scheme 2, example 1c) except using 20 (692 mg, 2.04 mmol) instead of 12 to afford 21 (278 mg, 78%) as a brown solid. LRMS (ESI): calc. 139.0; found 140.1 (MH)+.