HRID2196576

反应详情

EQUATION

反应方程式

HRID 2196576 的结构方程式

PROCEDURE

实验过程

The title compound 202 (1.04 g, 2.22 mmol, 71%) was prepared following the procedures described for the synthesis of 192 (scheme 33, Example 36, steps 5 and 6) using 201 (1.00 g, 3.13 mmol) in place of 190. LRMS (ESI): calc. 353.1, found 411.3 (MH)+.