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HRID220015

反应详情

EQUATION

反应方程式

HRID 220015 的结构方程式

REACTANTS

反应物

2
结构：CCOCCC(N)=NO
HCID5044387

3-ethoxy-N'-hydroxypropanimidamide

C5H12N2O2

结构：CCc1ccc(C2CC(C(=O)O)CN(C(=O)N3CCSCC3)C2)cc1
HCID58116464

未命名化合物

PRODUCTS

生成物

1
结构：CCOCCc1noc(C2CC(c3ccc(CC)cc3)CN(C(=O)N3CCSCC3)C2)n1
HCID59606585

未命名化合物

PROCEDURE

实验过程

According to General Method 6A, 600 mg (1.655 mmol) of the compound from Example 7A and 355 mg (approx. 2.152 mmol) of 3-Ethoxy-N′-hydroxypropanimidamide were reacted Yield: 389 mg (49% of theory)

WORKUP

后处理

  1. customwere reacted Yield: 389 mg (49% of theory)