Phosphorus oxychloride → HCID 19375606, compound
Reaction equation
[S:1]1[CH:5]=[CH:4][C:3]([C:6]2[C:15]3[C:10](=[CH:11][CH:12]=[CH:13][CH:14]=3)[C:9](=O)[NH:8][N:7]=2)=[CH:2]1.P(Cl)(Cl)([Cl:19])=O>ClC(Cl)C>[Cl:19][C:9]1[C:10]2[C:15](=[CH:14][CH:13]=[CH:12][CH:11]=2)[C:6]([C:3]2[CH:4]=[CH:5][S:1][CH:2]=2)=[N:7][N:8]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 100 °C
Procedure
500 mg of 4-(3-thienyl)-1-phthalazinone and 3 ml of phosphorus oxychloride were dissolved in 6 ml of dichloroethane, and the solution was stirred at 100° C. for 4 hours. The reaction solution was distilled off, and a 1-N aqueous NaOH solution was added thereto under cooling with ice. The solution was extracted with chloroform and dried over magnesium sulfide. The solvent was then distilled off, thereby obtaining 515 mg of 1-chloro-4-(3-thienyl)phthalazine.
Workup
- distillationThe reaction solution was distilled off
- additiona 1-N aqueous NaOH solution was added
- temperatureunder cooling with ice
- extractionThe solution was extracted with chloroform
- dry with materialdried over magnesium sulfide
- distillationThe solvent was then distilled off
Sources & evidence
- ORD record
- ord-70d91eeaabdc4a6bb4faa7d1f9c5bdd3
- Source dataset
- uspto-grants-1995_10
- Patent number
- US05462941
Reaction notes
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