HRID2216534

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID21943338

2-(Bromomethyl)-4'-chloro-4-methoxy-1,1'-biphenyl

C14H12BrClO

结构：COC(=O)/C(C)=C/c1cn(C2CCCCC2)c(-c2ccc(O)cc2)n1

HCID136341818

未命名化合物

PRODUCTS

生成物

结构：COC(=O)/C=C/c1cn(C2CCCCC2)c(-c2ccc(OCc3cc(OC)ccc3-c3ccc(Cl)cc3)cc2)n1

HCID11341937

未命名化合物

收率 73.2%

PROCEDURE

实验过程

According to the procedure for preparation of 4.4, phenol 12.9 (60 mg, 0.184 mmol) was alkylated with (4′-chloro-4-methoxy-1,1′-biphenyl-2-yl)methyl bromide (63 mg, 0.202 mmol), to yield 75 mg (73%) of 12.10. MS (ESI) 557.4 (MH+).

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-ee5eae4a1b084888b1ba8fc351c0edeb
来源数据集: uspto-grants-2006_09
DOI: 10.6084/m9.figshare.5104873.v1
专利: US07112601B2
来源说明: uspto-grants-2006_09

反应 SMILES

[OH:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2[N:9]([CH:20]3[CH2:25][CH2:24][CH2:23][CH2:22][CH2:21]3)[CH:10]=[C:11](/[CH:13]=[C:14](\C)/[C:15]([O:17][CH3:18])=[O:16])[N:12]=2)=[CH:4][CH:3]=1.[Cl:26][C:27]1[CH:32]=[CH:31][C:30]([C:33]2[CH:38]=[CH:37][C:36]([O:39][CH3:40])=[CH:35][C:34]=2[CH2:41]Br)=[CH:29][CH:28]=1>>[Cl:26][C:27]1[CH:28]=[CH:29][C:30]([C:33]2[CH:38]=[CH:37][C:36]([O:39][CH3:40])=[CH:35][C:34]=2[CH2:41][O:1][C:2]2[CH:7]=[CH:6][C:5]([C:8]3[N:9]([CH:20]4[CH2:25][CH2:24][CH2:23][CH2:22][CH2:21]4)[CH:10]=[C:11](/[CH:13]=[CH:14]/[C:15]([O:17][CH3:18])=[O:16])[N:12]=3)=[CH:4][CH:3]=2)=[CH:31][CH:32]=1