HRID2216535

反应详情

EQUATION

反应方程式

HRID 2216535 的结构方程式

PROCEDURE

实验过程

According to the procedure for preparation of 4.3, ester 13.1 (167 mg, 0.376 mmol) was treated with BCl3 (1.88 mmol) to yield 80 mg (60%) of 13.3. MS (ESI) 355.3 (MH+).