p-Fluoronitrobenzene → HCID 23725438, compound

HRID 2219339Notes

Reaction equation

[Br:1][C:2]1[CH:3]=[C:4]([C:8]2[C:12]([C:13]3[N:14]=[CH:15][NH:16][CH:17]=3)=[C:11]([CH3:18])[O:10][N:9]=2)[CH:5]=[CH:6][CH:7]=1.F[C:20]1[CH:25]=[CH:24][C:23]([N+:26]([O-:28])=[O:27])=[CH:22][CH:21]=1>>[Br:1][C:2]1[CH:3]=[C:4]([C:8]2[C:12]([C:13]3[N:14]=[CH:15][N:16]([C:20]4[CH:25]=[CH:24][C:23]([N+:26]([O-:28])=[O:27])=[CH:22][CH:21]=4)[CH:17]=3)=[C:11]([CH3:18])[O:10][N:9]=2)[CH:5]=[CH:6][CH:7]=1

Participants

Reactant 2

HCID 9590p-Fluoronitrobenzene

HCID 178434974HCID 178434974, compound

Product 1

HCID 23725438HCID 23725438, compoundYield 39%

Procedure

As described for Example 44, 3-(3-bromo-phenyl)-4-(1H-imidazol-4-yl)-5-methyl-isoxazole (91 mg, 0.3 mmol) using 1-fluoro-4-nitrobenzene instead of 4-fluoroacetophenone was converted to the title compound (50 mg, 39%) which was obtained as a light yellow solid. MS: m/e=425.1/427.1 [M+H]+.

Sources & evidence

ORD record: ord-3d82fe38e32c4632822aada8acd13338
Source dataset: uspto-grants-2008_08
DOI: 10.6084/m9.figshare.5104873.v1
Patent number: US07414061B2

Reaction notes

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