HRID2222429

反应详情

EQUATION

反应方程式

HRID 2222429 的结构方程式

PROCEDURE

实验过程

Using an analogous procedure to that described in Example 33, 4-chloro-6-cyano-7-(3-(pyrrolidin-1-yl)propoxy)quinoline (100 mg), (prepared as described for the starting material in Example 11), was reacted with 5-amino-2-methylindole (51 mg) to give 6-cyano-4-(2-methylindol-5-ylamino)-7-(3-(pyrrolidin-1-yl)propoxy)quinoline hydrochloride (58 mg, 37%).

WORKUP

后处理

  1. custom(prepared