HRID2224306

反应详情

EQUATION

反应方程式

HRID 2224306 的结构方程式

PROCEDURE

实验过程

Compound 5B (20.5 mg, 72.2%) was prepared from 1D (20.0 mg, 0.066 mmol) and 5A (28.7 mg, 0.099 mmol) by a route analogous to that used for the preparation of 2B. HPLC Rt=2.336 min; LCMS Found: (M+H)+=431.