HRID2224341

反应详情

EQUATION

反应方程式

HRID 2224341 的结构方程式

PROCEDURE

实验过程

The title compound (16.3 mg, 65%) was prepared from 41D (20 mg, 0.07 mmol) and 2A (24.7 mg, 0.105 mmol) by a route analogous to that used for the preparation of 2B. HPLC Rt=2.453 min; LCMS Found: (M+H)+=358.