HRID2224351

反应详情

EQUATION

反应方程式

HRID 2224351 的结构方程式

PROCEDURE

实验过程

Compound 52D (20.9 mg, 91%) was prepared from 52C (20 mg, 0.061 mmol) and 2A (14.3 mg, 0.061 mmol) by a route analogous to that used for the preparation of 2B. HPLC Rt=2.419 min; LCMS Found: (M+H)+=358.