HRID2224359

反应详情

EQUATION

反应方程式

HRID 2224359 的结构方程式

PROCEDURE

实验过程

Compound 64B (66.1 mg, 46%) was prepared from 64A (0.10 g, 0.5 mmol) and bb (82 mg, 0.5 mmol) in two steps by a route analogous to that used for the preparation of 1D. HPLC Rt=2.286 min; LCMS Found: (M+H)+=286.