Ethyl formate → HCID 178494763, compound
Reaction equation
C[O:2][CH:3]([C:5]1[NH:6][C:7]2[CH:13]=[CH:12][CH:11]=[CH:10][C:8]=2[N:9]=1)C.C([Li])CCC.[CH:19]([O:21][CH2:22][CH3:23])=O>CCCCCC>[CH3:19][O:21][CH:22]([C:13]1[C:7]2[NH:6][C:5]([CH:3]=[O:2])=[N:9][C:8]=2[CH:10]=[CH:11][CH:12]=1)[CH3:23]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
Following the procedure of Example 1D, 2.36 g of 1-methoxyethylbenzimidazole, 5.15 ml of 2.6M n-butyl lithium in hexane, 1.08 ml of ethyl formate gave on work-up 1.73 g of the desired product as a yellow oil.
Sources & evidence
- ORD record
- ord-251e3f5d000f49628012bb8f4b3fb29c
- Source dataset
- uspto-grants-1988_11
- Patent number
- US04782050
Reaction notes
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