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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 2232393Generated: October 25, 2026

2-Bromothiazole → 1-(5-Methylthien-2-yl)-2-(thiazol-2-yl)ethyne

https://huagongshe.com/reaction/2232393

Reaction equation

Participants

RoleNameHCIDCharge
Reactant2-BromothiazoleHCID 76430—
ReactantPotassium FluorideHCID 522689—
ReactantTetrabutylammonium FluorideHCID 2724141—
Reactant(5-Methyl-2-thienylethynyl)trimethylsilaneHCID 14643579—
SolventAcetonitrileHCID 6342—
SolventTriethylamineHCID 8471—
Product1-(5-Methylthien-2-yl)-2-(thiazol-2-yl)ethyneHCID 2128371541.8%

Reaction Steps

In a manner similar to Step E of Example 3, the reaction of 7.96 gram (0.0410 mole) of 1-trimethylsilyl-2-(5-methylthien-2-yl)ethyne, 1.23 gram (3.9×10-4 mole) of tetrabutylammonium fluoride, and 2.6 gram (0.045 mole) of potassium fluoride in 120 ml of triethylamine and 40 ml of acetonitrile with 6.39 grams (0.0390 mole) of 2-bromothiazole yielded 3.35 grams of 1-(5-methylthien-2-yl)-2-(thiazol-2-yl)ethyne as an oil.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS04788207
Source datasetuspto-grants-1988_11
ORD IDord-02ddcd7fba824f1689f1ce3482ca3f01
Source noteuspto-grants-1988_11