Sodium Hydroxide → HCID 58730647, compound

HRID 2233320Notes

Reaction equation

HRID 2233320 reaction equation
C[O:2][C:3](=[O:41])[CH2:4][CH:5]1[C:14]2[C:9](=[C:10]([F:15])[CH:11]=[CH:12][CH:13]=2)[N:8]=[C:7]([C:16]2[CH:21]=[CH:20][C:19]([C:22]3[CH:27]=[CH:26][CH:25]=[C:24]([CH3:28])[CH:23]=3)=[CH:18][CH:17]=2)[N:6]1[C:29]1[CH:34]=[C:33]([C:35]([F:38])([F:37])[F:36])[CH:32]=[CH:31][C:30]=1[O:39][CH3:40].[OH-].[Na+]>O1CCOCC1>[CH3:28][C:24]1[CH:23]=[C:22]([C:19]2[CH:18]=[CH:17][C:16]([C:7]3[N:6]([C:29]4[CH:34]=[C:33]([C:35]([F:38])([F:37])[F:36])[CH:32]=[CH:31][C:30]=4[O:39][CH3:40])[CH:5]([CH2:4][C:3]([OH:41])=[O:2])[C:14]4[C:9](=[C:10]([F:15])[CH:11]=[CH:12][CH:13]=4)[N:8]=3)=[CH:21][CH:20]=2)[CH:27]=[CH:26][CH:25]=1

Participants

4

Reactant 2

HCID 14798Sodium HydroxideHCID 58730638HCID 58730638, compound

Product 1

HCID 58730647HCID 58730647, compound

Reagents, catalysts & solvents 1

HCID 312751,4-DioxaneSolvent

Procedure

Starting from 450 mg (0.80 mmol) of the ester from Example 21A, reaction in analogy to general method [E] with 96 mg (2.40 mmol) of sodium hydroxide in 21.5 ml of dioxane results in 407.5 mg (93% of theory) of the target compound.

Workup

  1. customresults in 407.5 mg (93% of theory) of the target compound

Sources & evidence

ORD record
ord-f93d427a9f814d088dd2ae7d06498c82
Source dataset
uspto-grants-2010_05
Patent number
US07709491B2

Reaction notes

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