HRID2243610

反应详情

EQUATION

反应方程式

HRID 2243610 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

1

PROCEDURE

实验过程

25 is prepared similarly to 24 starting from 500 mg of 2,3,4-triacetoxy-1-{2-[2-(2-aminoethoxy)ethoxy]acetyl}-5-hydroxypentyl acetate 23, 927 mg of (2-carboxymethoxyethoxy)acetic acid, 400 μl of diisopropylcarbodiimide and 288 mg of hydroxybenzotriazole in 20 ml of methylene chloride. This gives 25: