Isopropanol → 6-(3-Methoxyphenyl)-4-Propylmorpholin-3-one

HRID 2252627Notes

Reaction equation

HRID 2252627 reaction equation
[OH-].[K+].C(O)(C)C.Cl[CH2:8][C:9]([N:11]([CH2:15][CH:16]([OH:25])[C:17]1[CH:22]=[CH:21][CH:20]=[C:19]([O:23][CH3:24])[CH:18]=1)[CH2:12][CH2:13][CH3:14])=[O:10]>O>[CH3:24][O:23][C:19]1[CH:18]=[C:17]([CH:16]2[CH2:15][N:11]([CH2:12][CH2:13][CH3:14])[C:9](=[O:10])[CH2:8][O:25]2)[CH:22]=[CH:21][CH:20]=1

Participants

5

Procedure

Potassium hydroxide (4.2 g, 0.07 mol), isopropyl alcohol (500 ml) and the amide from example 4 (17.8 g, 0.06 mol) were stirred together as an opaque solution with water (15 ml) for 2 hours. The reaction mixture was concentrated in vacuo and the yellow residue dissolved in ethyl acetate (200 ml). This was partitioned with water (200 ml) then brine (200 ml). The organic fraction was dried over anhydrous magnesium sulphate, filtered and concentrated in vacuo to give the title compound as a yellow oil (15.8 g, 0.06 mol, 100%). 1H NMR (CDCl3, 400 MHz) δ: 0.96 (t, 3H), 1.62 (m, 2H), 3.36 (m, 2H), 3.51 (q, 2H), 3.81 (s, 3H), 4.30-4.62 (bq, 2H), 4.79 (d, 1H), 6.85 (d, 1H), 6.91 (d, 1H), 6.95 (s, 1H), 7.29 (t, 1H). LRMS: m/z 272. Analysis found C, 66.80; H, 7.78; N, 5.52%. C14H19NO3.0.1H2O requires C, 66.96; H, 7.71; N, 5.58%.

Workup

  1. concentrationThe reaction mixture was concentrated in vacuo
  2. dissolutionthe yellow residue dissolved in ethyl acetate (200 ml)
  3. customThis was partitioned with water (200 ml)
  4. dry with materialThe organic fraction was dried over anhydrous magnesium sulphate
  5. filtrationfiltered
  6. concentrationconcentrated in vacuo

Sources & evidence

ORD record
ord-0b19b197cb88447ebe9ad33b57e91c4f
Source dataset
uspto-grants-2008_01
Patent number
US07323462B2

Reaction notes

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