Glycidol → HCID 19745105, compound
Reaction equation
[NH2:1][C:2]1[CH:7]=[CH:6][C:5]([CH2:8][CH2:9][CH2:10][C:11]2([CH3:16])[O:15][CH2:14][CH2:13][O:12]2)=[CH:4][CH:3]=1.[CH2:17]1[O:19][CH:18]1[CH2:20][OH:21]>C(O)C>[OH:19][CH:18]([CH2:20][OH:21])[CH2:17][NH:1][C:2]1[CH:7]=[CH:6][C:5]([CH2:8][CH2:9][CH2:10][C:11]2([CH3:16])[O:12][CH2:13][CH2:14][O:15]2)=[CH:4][CH:3]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
To a solution of 10 g (0.045 mol) of 230113 (Example 9--Step 3) in 60 ml of ethanol, are added 3.34 g (0.045 mol) of glycidol and left under stirring overnight. After concentration, the product is obtained by chromatography (silica, eluent: CH2Cl2 :97, CH3OH:3); Yield=44%.
Workup
- waitleft
- concentrationAfter concentration
- customthe product is obtained by chromatography (silica, eluent: CH2Cl2 :97, CH3OH:3)
Sources & evidence
- ORD record
- ord-838ae78a9d4d42f09f49db21b3a67c6c
- Source dataset
- uspto-grants-1993_08
- Patent number
- US05235063
Reaction notes
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