HRID2258450

反应详情

EQUATION

反应方程式

HRID 2258450 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

1

PROCEDURE

实验过程

By the method described in Example 16, the title compound of Example 24 (0.82 g, 2.0 mmol) in 40 mL of MeOH was treated with 2N HCl/MeOH (5 mL) to produce 0.25 g of the title product.