Tert-Butylamine → 4-bromo-N-tert-butylbenzamide
Reaction equation
[C:1]([NH2:5])([CH3:4])([CH3:3])[CH3:2].[Br:6][C:7]1[CH:15]=[CH:14][C:10]([C:11](Cl)=[O:12])=[CH:9][CH:8]=1>C1C=CC=CC=1>[C:1]([NH:5][C:11](=[O:12])[C:10]1[CH:14]=[CH:15][C:7]([Br:6])=[CH:8][CH:9]=1)([CH3:4])([CH3:3])[CH3:2]Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
The preparation of Example 1 was repeated with the changes that tert-butyl amine (4.02 g, 0.055 mole) and 4-bromobenzoyl chloride (6.04 g, 0.0275 mole) were the starting reactants and benzene was the reaction medium. This reaction produced 6.24 g crystals (89% yield), mp 130°-133° C. Proton nuclear magnetic resonance (89.55 MHz) showed absorptions at 7.562 ppm (s, 4H; aryl H); 5.910 ppm (bs, 1H; N-H); 1.464 ppm (s, 9H; tert-butyl H).
Workup
- customThe preparation of Example 1
Sources & evidence
- ORD record
- ord-ed9a7e7125504a419ad0ebc4531f49be
- Source dataset
- uspto-grants-1995_12
- Patent number
- US05472983
Reaction notes
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