Phosgene → 9(+)-Fluorenylethyl chloroformate
Reaction equation
[CH:1]1[C:13]2[CH:12]([CH2:14][CH2:15][OH:16])[C:11]3[C:6](=[CH:7][CH:8]=[CH:9][CH:10]=3)[C:5]=2[CH:4]=[CH:3][CH:2]=1.[C:17](Cl)([Cl:19])=[O:18]>C1(C)C=CC=CC=1.O1CCCC1>[Cl:19][C:17]([O:16][CH2:15][CH2:14][CH:12]1[C:13]2[CH:1]=[CH:2][CH:3]=[CH:4][C:5]=2[C:6]2[C:11]1=[CH:10][CH:9]=[CH:8][CH:7]=2)=[O:18]Participants
5
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
To a solution of 2-(9-fluorenyl)ethanol 1.26 g, 6 mmol) in 10 ml of toluene and 4 ml of tetrahydrofuran (THF), was added dropwise with stirring phosgene (12.4 ml, 1.93M solution in toluene). The solution was stirred for 0.5 hours, then put under vacuum to remove the phosgene. Concentration yielded 2-(9-fluorenyl)ethyl chloroformate (6 mmol, 1.64 g).
Workup
- customto remove the phosgene
- concentrationConcentration
Sources & evidence
- ORD record
- ord-b5cd0131fbb0413fb4cb54a14a750b07
- Source dataset
- uspto-grants-1995_12
- Patent number
- US05472973
Reaction notes
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