HRID2266001

反应详情

EQUATION

反应方程式

HRID 2266001 的结构方程式

PROCEDURE

实验过程

3-(2-Chloro-6-trifluoromethyl-pyridin-3-yl)-N-(3-ethynyl-5-fluoro-4-methanesulfonylamino-benzyl)-acrylamide (50 mg, 0.11 mmol) and 3-hydroxytetrahydrofuran (18 μl, 0.22 mmol) was reacted as in example 72 to give the title compound (23 mg, 21%).