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HRID2269479

反应详情

EQUATION

反应方程式

HRID 2269479 的结构方程式

REACTANTS

反应物

2
结构：O=C(c1ccc(F)cc1)c1cccc([N+](=O)[O-])c1
HCID10490558

4-FLUORO-3'-NITROBENZOPHENONE

C13H8FNO3

结构：C[C@@H](N)c1ccc(F)c(F)c1.Cl
HCID45072357

(1R)-1-(3,4-Difluorophenyl)ethan-1-amine--hydrogen chloride (1/1)

C8H10ClF2N

PRODUCTS

生成物

1
结构：C[C@@H](NC(c1ccc(F)cc1)c1cccc([N+](=O)[O-])c1)c1ccc(F)c(F)c1
HCID70189099

未命名化合物

收率 90.8%

PROCEDURE

实验过程

Following a similar procedure to that described in Example (1a), 12.91 g of 4-fluorophenyl 3-nitrophenyl ketone and 10.19 g of (R)-1-(3,4-difluorophenyl)ethylamine hydrochloride were reacted, to obtain 18.47 g of the title compound as a pale yellow oil.

WORKUP

后处理

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