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HRID2269481

反应详情

EQUATION

反应方程式

HRID 2269481 的结构方程式

REACTANTS

反应物

2
结构：COc1ccc(C(=O)c2cccc([N+](=O)[O-])c2)cc1
HCID794540

(4-methoxyphenyl)(3-nitrophenyl)methanone

C14H11NO4

结构：C[C@@H](N)c1cccc(F)c1.Cl
HCID45072322

(1R)-1-(3-Fluorophenyl)ethan-1-amine--hydrogen chloride (1/1)

C8H11ClFN

PRODUCTS

生成物

1
结构：COc1ccc(C(N[C@H](C)c2cccc(F)c2)c2cccc([N+](=O)[O-])c2)cc1
HCID70188098

未命名化合物

PROCEDURE

实验过程

Following a similar procedure to that described in Example (1a), 11.16 g of 4-methoxyphenyl 3-nitrophenyl ketone and 7.62 g of (R)-1-(3-fluorophenyl)ethylamine hydrochloride were reacted, to obtain 15.11 of the title compound as a pale yellow oil.

WORKUP

后处理

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