huagongshe.com
HRID22707

反应详情

EQUATION

反应方程式

HRID 22707 的结构方程式

REACTANTS

反应物

4
结构：CC(=O)Oc1ccc([N+](=O)[O-])cc1
HCID13243

Acetic acid, 4-nitrophenyl ester

C8H7NO4

结构：COc1ccc(O)c([N+](=O)[O-])c1
HCID15285

Phenol, 4-methoxy-2-nitro-

C7H7NO4

结构：COc1ccc(O)c(N)c1
HCID1419108

2-amino-4-methoxyphenol

C7H9NO2

结构：CC(=O)Oc1ccc(NC(=O)CCl)cc1
HCID22591610

未命名化合物

PRODUCTS

生成物

1
结构：CC(=O)Oc1ccc(N)cc1
HCID83783

Phenol, 4-amino-, acetate (ester)

C8H9NO2

PROCEDURE

实验过程

Compound 55 was prepared in the manner of compound 12 substituting 4-nitrophenyl acetate for compound 11 in part C-1 of Example 1. Synthesis of 4-(2-chloroacetylamino)phenyl acetate (56):