Benzoic Acid → Vinyl benzoate
Reaction equation
[C:1]([OH:9])(=[O:8])[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1.[C:10](OC=C)(=O)[CH3:11]>[Pd]>[C:1]([O:9][CH:10]=[CH2:11])(=[O:8])[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
Analogously to the procedure described in Example I, 0.285 g of the polymer prepared according to Example 16 and having a palladium content of 18.5% by weight, are warmed to 60°-65° C. with 12.2 g of benzoic acid and 55.4 ml of vinyl acetate. After 29 hours, 11.3 g of vinyl benzoate have formed, corresponding to a yield of 76% of theory. Using the recovered catalyst, 10.4 g of vinyl benzoate, corresponding to 70.5% of theory are again obtained after 20 hours in a further reaction batch.
Workup
- customprepared
Sources & evidence
- ORD record
- ord-b9da9b58538341e1ab0ccb90a47cb736
- Source dataset
- uspto-grants-1984_01
- Patent number
- US04424359
Reaction notes
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