HRID2300635

反应详情

EQUATION

反应方程式

HRID 2300635 的结构方程式

PROCEDURE

实验过程

The title compound was prepared (as described above for the preparation of Example 2) from 1.0 g (2.05 mmol) of Intermediate 45 (as the TFA salt) and 0.86 g (4.2 mmol) of Intermediate 18 to yield 290 mg (25% yield) of Example 23 as a solid: TLC (EtOAc/MeOH , 7/3): Rf=0.55; 1H NMR (DMSO-d6, 400 MHz) δ11.59 (d, 1H, J=9.7), 7.86 (m, 2H), 7.76 (m, 2H), 7.48-7.34 (m, 6H), 7.10 (d, 2H, J=8.5), 7.10 (t, 2H, J=8.4), 6.8 (d, 2H, J=8.6), 5.52 (s, 1H), 4.12 (t, 2H, J=6.5), 4.02 (m, 1H), 3.16 (m, 1H), 2.86 (t, 2H, J=6.5), 2.75 (dd, 1H, J=13.5, 9.5), 2.31 (s, 3H), 1.9 (m, 2H), 1.3-1.1 (m, 4H), 0.73 (t, 3H, J=6.9); low resolution MS (ES+)m/e 553.2 (MH+).