Iodoethane → 4-ethoxy-tetrahydro-4-(4-iodophenyl)-2H-pyran
Reaction equation
[I:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2([OH:14])[CH2:13][CH2:12][O:11][CH2:10][CH2:9]2)=[CH:4][CH:3]=1.I[CH2:16][CH3:17]>>[CH2:16]([O:14][C:8]1([C:5]2[CH:6]=[CH:7][C:2]([I:1])=[CH:3][CH:4]=2)[CH2:9][CH2:10][O:11][CH2:12][CH2:13]1)[CH3:17]Participants
3
Procedure
In the same manner as in Reference Example 2, tetrahydro-4-(4-iodophenyl)-2H-pyran-4-ol (302 mg) and iodoethane (0.119 ml) were reacted to obtain 4-ethoxy-tetrahydro-4-(4-iodophenyl)-2H-pyran (269 mg).
Sources & evidence
- ORD record
- ord-ceeba7aad87142b8b3ac2366ce9573fc
- Source dataset
- uspto-grants-2009_07
- Patent number
- US07566724B2
Reaction notes
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