(4-Chlorophenyl)acetic acid → 4-Chlorophenylacetyl chloride
Reaction equation
[Cl:1][C:2]1[CH:7]=[CH:6][C:5]([CH2:8][C:9]([OH:11])=O)=[CH:4][CH:3]=1.S(Cl)([Cl:14])=O>C(Cl)(Cl)Cl>[Cl:1][C:2]1[CH:7]=[CH:6][C:5]([CH2:8][C:9]([Cl:14])=[O:11])=[CH:4][CH:3]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
To 100 mL of chloroform is added 4-chlorobenzeneacetic acid (17 g, 0.1 mol) and 24 g (0.2 mol) of thionyl chloride. Reflux the reaction mixture for 3 hours and remove the solvent in vacuo to give the title compound.
Workup
- temperatureReflux the reaction mixture for 3 hours
- customremove the solvent in vacuo
Sources & evidence
- ORD record
- ord-b5c0cdb5c426458bb669b3eccacbbbc5
- Source dataset
- uspto-grants-1989_07
- Patent number
- US04851526
Reaction notes
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